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3x^2+27x-66=0
a = 3; b = 27; c = -66;
Δ = b2-4ac
Δ = 272-4·3·(-66)
Δ = 1521
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{1521}=39$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(27)-39}{2*3}=\frac{-66}{6} =-11 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(27)+39}{2*3}=\frac{12}{6} =2 $
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